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Rotating cylinder, how long will it take before the angular velocity is halved

  1. Mar 25, 2007 #1
    1. The problem statement, all variables and given/known data

    A flywheel has shape as a homogeneous cylinder with mass m = 40,0 kg and radius r = 0,50 meters. The cylinder is rotating round the axis of symmetry, and is runned by a motor with constant angular velocity (w0). When the motor is switched off, the cylinder is affected by a moment of force that are caused by friction.
    How long will the cylinder rotate before the angular velocity is halved?


    2. Relevant equations

    The friction: M = -kw
    w = omega
    k = (1,2 * 10^2) Nm/s


    3. The attempt at a solution

    The moment of inertia: I = (m*r^2)/2 (cylinder)

    M = -kw => 1) w = -(M/k)

    w = 1/2*w0

    alpha = w/T = (1/2*w0)/T

    1) (1/2*w0) = -(M/k)

    (1/2*w0) = -((I*alpha)/k)

    (1/2*w0) = -((((m*r^2)/2)*((1/2*w0)/T))/k)

    When solving this equation the answer is: T = -416
    BUT sadly we are quite sure this answer is incorrect, any help will be appreciated.
     
  2. jcsd
  3. Mar 25, 2007 #2
    This exercice would have been more funny if only the absorbed power before switch-off had been given, and not the friction factor "k".

    Anyway, you need to solve the equation of motion.
    You should write the equation of motion, to make your derivation clearer,
    and it could help you too.
     
  4. Mar 25, 2007 #3

    Mentz114

    User Avatar
    Gold Member

    Aha. Please see my post in your earlier thread.
     
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