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## Homework Statement

There is one square coil of area A that rotates with speed [tex]\omega[/tex] around axis y. The magnetic field is uniform and points to the z direction. Show that the torque is [tex]\frac{A^2B^2N^2\omega sin\omega t}{R}[/tex].

## Homework Equations

[tex]T = |\underline{m} \times \underline{B}|[/tex]

[tex]\underline{m} = N I A[/tex]

Thus [tex]T = NIABcos(\omega t)[/tex]

Unsure about these:

[tex]EMF = NIR[/tex]

[tex]EMF = - N\frac{d \Phi}{d t}[/tex]

## The Attempt at a Solution

Now I have read many similar questions on this forums, and I think I am close to fully understand the problem itself, but there is a piece missing, and I don't see from my initial equations where I am going wrong.

I calculate I via the EMF, substitute it into T. But with this I end up with one N, whereas the supposed solution that I need to prove in the exercise is [tex]T = \frac{A^2B^2\omega sin^2\omega t}{R}[/tex].

I am assuming one of the initial equations wrong, I suspect the EMF section, because I not understand it. Any help would be appreciated.

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