Rotational Dynamics Designing a Propeller Velocity/Acceleration

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The discussion revolves around designing a propeller for an airplane with specific speed and rotational requirements. The problem states that the propeller must not exceed a tip speed of 270 m/s while turning at 2400 rpm and moving forward at 75.0 m/s. There is confusion regarding the calculations for the maximum radius of the propeller, with one participant arriving at 1.07 m while the textbook solution provides 1.03 m. The key point is that the maximum speed of 270 m/s must account for both the tangential speed of the propeller and the forward speed of the airplane, necessitating the use of the Pythagorean theorem to find the overall velocity. Ultimately, understanding the components of velocity is crucial for solving the problem correctly.
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Homework Statement


You are asked to design an airplane propleller to turn at 2400 rpm. The forward airspeed of the plane is to be 75.0 m/s, and the speed of the tips of the propeller blades through the air must not exceed 270 m/s. What is the maximum radius the propeller can have? With this radius, what is the acceleration of the propeller tip?

Homework Equations


v = rw
alpha = omega^2 (r)

The Attempt at a Solution



My issue with this problem is after trying to understand the explained solution. This problem is an example in my physics book.

Both the book and I convert the 2400 rpm into rad/s

(2400(2)pi)/60 = 251 rad/s

This is where I get confused. I simply divide as so, v= rw , so v/w = r

270/251 = 1.07 m

The book doesn't do this, instead it says V_tip^2 = V_plane^2 + V_tan^2 = V_plane^2 + (r^2)(w^2)
They then solve for r and get r = 1.03 vs what I got, 1.07.

What exactly are they accounting for is I think what I am trying to understand. Thanks in advance.
 
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You are forgetting the velocity component in the forward direction (which is orthogonal to the tangential, hence Pythagoras).

Edit: To expand on that, the problem states that the tips have a max velocity through the air - not relative to the centre of the propeller. The entire propeller moves relative to the air.
 
Thanks for the assistance. I'm still a bit confused. Are you saying that since the problem defined the 270 m/s velocity limit through the air as both components of velocity , tangential and otherwise, I need to account for both components?

I have this inkling that it might help if you would kindly speculate on the wording the book would use if I didn't need to account for the forward velocity of the plane. As I read it now, I was under the impression that I should disregard it.

Thank you again, and I do apologize if I'm wearing on your patience.
 
hitspace said:
Are you saying that since the problem defined the 270 m/s velocity limit through the air as both components of velocity , tangential and otherwise
Not sure what you mean by that. It defines 270 m/s as the maximum speed of the tip relative to the air. Speed is the magnitude of the overall velocity. You have two components, tangential and forward, at right angles to each other, so to find the magnitude of the overall velocity vector you can use Pythagoras.
 
hitspace said:
I have this inkling that it might help if you would kindly speculate on the wording the book would use if I didn't need to account for the forward velocity of the plane. As I read it now, I was under the impression that I should disregard it

It would say something like "tangential speed" or "rotational speed". As posed, it is rather clear that it means overall speed.
 
Thanks for the insight. I appreciate you taking the time to help me out.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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