1. The problem statement, all variables and given/known data In the figure here, a small, solid, uniform ball is to be shot from point P so that it rolls smoothly along a horizontal path, up along a ramp, and onto a plateau. Then it leaves the plateau horizontally to land on a game board, at a horizontal distance d from the right edge of the plateau. The vertical heights are h1 = 4.5 cm and h2 = 1.00 cm. With what speed must the ball be shot at point P for it to land at d = 3.5 cm? 2. Relevant equations E'=E Translational KE = mv^2/2 Rotational KE = Iω^2/2 y = y0 + v0T + aT^2/2 3. The attempt at a solution (0.5)mv0^2 = (0.5)mv'^2 + mgh1 Which simplifies to v0 = sqrt(2gh1 + v'^2) (1) To find v': d = v'T => v' = d/T To find T: h2 = (0.5)gT^2 => T = sqrt(2h2/2) So, v' = d/sqrt(2h2/2) which is approximately 0.77 m/s. Plugging this into (1) v0 = 1.217 m/s. However, this is not the right answer. So, I then attempted it again this time taking into account that the moment of inertia of a solid sphere is (2/5)mR^2. (0.5)(2/5)(mR^2)ω0^2 = (0.5)(2/5)(mR^2)ω'^2 + mgh1 v = rω (1/5)(mR^2)v0^2/R^2 = (1/5)(mR^2)v'^2/R^2 + mgh1 v0^2 = v'^2 + 5gh1 v0 = sqrt(v'^2 + 5gh1) Then v' is the same in this attempt as the previous, so v0 = 1.67 m/s. However, this is also not the right answer. It appears there is not enough information to take into account energy lost to friction so I'm assuming that's negligible. So, I'm at a loss.