Rotational Equilibrium and Dynamics Question

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SUMMARY

The discussion focuses on solving a rotational equilibrium problem involving a uniform ladder. The ladder, measuring 8.00 meters and weighing 200.0 N, is positioned against a smooth wall at a 50-degree angle. An 800.0 N person can climb the ladder until it begins to slip, which requires calculating the tension forces and moments around specific points. The method involves summing moments about the line through T2 and P to eliminate variables and determine the critical point of slipping.

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1) If you go to this site it has the question already set up. the one I need help on is question number 62, the picture frame one. I know that the answers are already given but I want to know how this is set up.

http://www.phys.uvic.ca/vannetten/phys102/Assignments/t1a9p.pdf

2) A uniform ladder 8.00 m long and weighing 200.0 N rests against a smooth wall. The coefficient of static friction between the ladder and the ground is 0.600, and the ladder makes a 50 degree angle withthe ground. How far up th eladder can an 800.0 N person climb before the ladder begins to slip?

Thanks in advance
 
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Sum the moments about the line passing through T2 and P (This will eliminate both), this will give you the tension for T1. Now Sum moments at the line through T2 and T1 to find P (this will eliminate T2 and T1), and then sum forcess to find P.
 

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