Rotational Equilibrium Problem

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
2 replies · 2K views · last reply
JoeyBob
Messages
256
Reaction score
29
Homework Statement
See attached
Relevant Equations
T=r x F
See attached file. Answer is supposed to be 61.25 N, I get 20.09 N.
 
Attachments
  • Handwritten sketch of a horizontal bar with T1 on the left and T2 on the right, a dashed length marked 3L/4 from the left end, and a mass labelled m hanging below.
    Question.PNG
    10.5 KB · Views: 212
  • Handwritten torque equilibrium derivation: 0 = T_rope1 + T_rope2 + T_gravity, expanded with cross products, reducing to T1 - 0.25 mg, giving T1 = 0.25 mg, boxed as 20.09. Small sketch of a bar with a pivot labelled origin.
    Attempted solution.jpg
    32.1 KB · Views: 213
Physics news on Phys.org
There are 4 forces acting on the bar. You show only 3 in your attempt.
 
kuruman said:
There are 4 forces acting on the bar. You show only 3 in your attempt.
Thanks, I got it.