- See picture
- Torque = Fnet x L
The system is in rotational equilibrium and therefore experiences no net torque, meaning all individual torques must add to zero.
τNET = 0 = FFTsin(θ)L - FgL - Fg(L/2)
τNET = 0 = FTsin30°(0.6???) - (0.5)(9.8)(0.6) - (2.0)(0.6/2)
My only problem (I think) is figuring out what the length L is for the cord holding the spring scale.