Rotational Freq of Wheel for "Artificial Gravity" of 9.3 m/s^2

[rrodriguez119]

1. A space station in the form of a large wheel, 124 m in diamete, rotates to provide and "artificial gravity" of 9.3 m/s^2 for people located on the outer rim.

Find the rotational frequency of the wheel that will produce this effect.
(answer in units of rpm)

2. v^2=gr, w=v/r, w/2pi = frequency


3. To find velocity I used v^2=gr. I know that w=v/r so with my found velocity I divided it by the radius (62). to find the frequency=> w/2pi = frequency. I must be missing a step because the answer I got is wrong. Help would be fancied. thank you!

 

[PhanthomJay]

The number you calculated for frequency is probably expressed in revolutions (cycles) per second (I'm guessing, since you did not show how you arrived at whatever answer you got). The question asks for revolutions per minute (rpm). You must watch units!

 

[rrodriguez119]

The number you calculated for frequency is probably expressed in revolutions (cycles) per second (I'm guessing, since you did not show how you arrived at whatever answer you got). The question asks for revolutions per minute (rpm). You must watch units!

what would you do?

 

[rrodriguez119]

nvm, I understand what i have to do. thanks!