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Rotational Kinetic Energy of Cl2?

  • Thread starter XianForce
  • Start date
  • #1
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Homework Statement


In a crude model of a rotating diatomic molecule of chlorine (Cl2), the two Cl atoms are 2.00 10^-10 m apart and rotate about their center of mass with angular speed ω = 3.80 10^12 rad/s. What is the rotational kinetic energy of one molecule of Cl2, which has a molar mass of 70.0 g/mol?


Homework Equations



1/2 * m * v2 (Kinetic Energy)

v/2 * KB * T (Internal Energy of a molecule)

The Attempt at a Solution


I attempted to use the equation for kinetic energy, substituting r * ω for v, but my web assign says that this is wrong. Nothing like this was taught in class and the book does not say much, so I'm at a loss for where to go.
 

Answers and Replies

  • #2
ehild
Homework Helper
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The rotational energy of a rigid body (like the Cl2 molecule) is Erot=1/2 Iω2, where I is the moment of inertia and ω is the angular speed of rotation.

The Cl2 molecule can be considered as two point masses d distance apart, rotating around a bisector of the connecting line. So the moment of inertia is 1/2 md^2.

There are two mutually perpendicular axis of rotation so the molecule has got two rotational degrees of freedom.

ehild
 
  • #3
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So basically: 1/4 * 1 mol /(6.022 * 1023) * (70 * 10-3) kg/mol * (780 m/s)2 = 1.768 * 10-20 J , right? But Web Assign keeps telling me that's wrong, so where am I making the mistake?
 
  • #4
ehild
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Explain your calculation. What is that 780 m/s?

ehild
 
  • #5
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Nevermind, I figured it out. It's m (d/2)^2, not 1/2 * md^2
 
  • #6
ehild
Homework Helper
15,477
1,854
Nevermind, I figured it out. It's m (d/2)^2, not 1/2 * md^2
Well done!

ehild
 

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