Constant rotational kinetic energy

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SUMMARY

The discussion centers on the concept of constant rotational kinetic energy in a system where a mass m is attached to a string and moves in a circular path on a frictionless table. As the string is pulled, reducing the radius of the circle, the work done is questioned in relation to the constancy of rotational kinetic energy. It is established that while work is performed, the rotational kinetic energy remains constant due to the conservation of angular momentum, as no external torque acts on the system.

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fib1123
Moved from a technical forum, so homework template missing.
A mass m is attached at the end of the string. The mass moves on a frictionless table, and the string passes through a hole in the table, under which someone is pulling on the string to make it taut at all times. Initially , the mass moves in a circle, with kinetic energy [E][/0] . The string is slowly pulled, until the radius of the circle is halved. How much work is done?
upload_2017-11-20_15-15-19.png

I calculated the work and the result is
upload_2017-11-20_15-16-15.png

but my question is: Why is the rotational kinetic energy constant during the motion?
 

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fib1123 said:
A mass m is attached at the end of the spring.
String?
fib1123 said:
Why is the rotational kinetic energy constant during the motion?
Work is done, so kinetic energy must change. The angular momentum is constant, because there is not torque.
 

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