Rotational Motion dynamics problem

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SUMMARY

The discussion centers on a rotational motion dynamics problem involving a giant yo-yo with a mass of 400 kg and a radius of 1.2 m, dropped from a height of 63 m. The participant initially calculated the acceleration as a = 2g/3 but received incorrect results. Key equations utilized include F = ma, τ = I * α, and I = mr²/2. The critical insight provided emphasizes the distinction between the yo-yo's radius (1.2 m) and the axle's radius (0.1 m) when calculating torque and moment of inertia.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Familiarity with rotational dynamics concepts (torque and angular acceleration)
  • Knowledge of moment of inertia calculations (I = mr²/2)
  • Basic kinematic equations for motion (x = 0.5at²)
NEXT STEPS
  • Review the derivation of torque in rotational systems using τ = Iα
  • Study the relationship between linear and angular acceleration in rotational motion
  • Explore the effects of moment of inertia on the dynamics of rolling objects
  • Practice solving similar problems involving rotational motion and free fall
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and rotational dynamics, as well as educators seeking to clarify concepts related to torque and moment of inertia.

miamirulz29
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Homework Statement


A giant yo-yo of mass 400 kg measuring about 1.2 m in radius was dropped from a platform 63 m high. One end of the string was tied to the platform, so the yo-yo unwinds as it descended. Assuming that the axle of the yo-yo has a radius of .1 m, find the velocity of descent at the end of the fall. the acceleration of gravity is 9.81. Answer in units of m/s.


Homework Equations


F = ma
Tau = I * alpha
I = mr^2/2

The Attempt at a Solution


mg-T = ma
rT = I * alpha
I solved for a and got a = 2g/3.

I then used that acceleration to find how the time it took to descend.
x = .5at^2, x being the height of the platform.

Once I found t, I found v using:
v = at.

The answer I got was incorrect. Could somebody please tell me what I am doing incorrectly? Thanks in advance.
 
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miamirulz29 said:

Homework Equations


F = ma
Tau = I * alpha
I = mr^2/2

The Attempt at a Solution


mg-T = ma
rT = I * alpha
I solved for a and got a = 2g/3.
I'm not quite sure where you got your expression for a, but I came up with something much smaller.

A possible bit of advice is to take care with the fact that there are two 'r's involved.
  • There's the 1.2 m radius of the entire yo-yo. This is important when calculating the yo-yo's moment of inertia, I.
  • Then there is the 0.1 m radius of the axle. This is the one to use when torques and such are involved, like τ = Iα (where τ is the torque).
    [Edit: in other words, it's the 0.1 m radius of the axle -- not the 1.2 m radius of the entire yo-yo -- that relates torque to force (once the moment of inertia has already been calculated) and angular acceleration to linear acceleration.]
 
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