Yo-Yo Homework: Find Average Force on String

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SUMMARY

The discussion revolves around calculating the average force on a string when a Yo-Yo, with a mass M and moment of inertia MR²/2, is released from rest and descends a distance h. Key equations include the relationship between linear velocity (v), angular velocity (α), and energy conservation principles. The participant successfully calculated the final angular velocity (ω) but struggled to determine the average force due to confusion over the implications of uniform spin velocity and angular momentum changes at the bottom of the string.

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Homework Statement



A Yo-Yo of mass M has an axle of radius b and a spool of radius R. Its moment of inertia can be taken to be MR^{2}/2 and the thickness of the string can be neglected. The Yo-Yo is released from rest. The center of the Yo-Yo descends distance h before the string is fully unwound. Assuming it reverses direction with uniform spin velocity, find the average force on the string when the Yo Yo turns around.

Homework Equations



v=bα v = linear velocity of the yoyo. α= angular velocity of the yoyo.

\frac{1}{2}Mv^{2} + \frac{1}{2}Iω^{2} = Mgh

The Attempt at a Solution



From the constraint equation and the energy conservation I calculated final ω. Now change in angular momentum is 2Iω. Now I can't find the average force from here.
 
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You are asked to assume a uniform spin velocity - since the rotation changes neither rate not direction (constant velocity) how does it change angular momentum?

What changes direction when the yo-yo reaches the bottom of the string?

You do have a problem with "average force" though ... what would this mean?
 

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