- #1

jeeves_17

- 10

- 0

**A 200 g, 20-cm-diameter plastic disk is spun on an axle through its**

center by an electric motor. What torque must the motor supply to take

the disk from 0 to 1800 rpm in 4.0s? (Given: I = ½ MR2)

center by an electric motor. What torque must the motor supply to take

the disk from 0 to 1800 rpm in 4.0s? (Given: I = ½ MR2)

**Relevant equations**

I = 1/2 MR^2

T = Ia

**The attempt at a solution**

v=0.02m * 1800 rev/min / 4 sec * 60 sec / 1 min * 2 Pi / 1 Rev

v= 10 800 m/s

a = how do i get this?

I = 1/2 (0.2kg)(0.1)^2

I = 0.001

T = Ia

T = (0.001)a

T = answer

is this correct?