logan
got it was 6.7x10^-2
thanks haruspex and cwatters
thanks haruspex and cwatters
The discussion centers on calculating the torque required to spin a 250g plastic disk with a diameter of 25 cm from 0 to 1500 RPM in 4.6 seconds. Participants clarify the use of the equation τ = Iα, where τ is torque, I is moment of inertia, and α is angular acceleration. The moment of inertia for the disk is calculated using the formula I = 1/4 * m * r², resulting in a value of approximately 0.067 Nm. The conversion from RPM to radians per second is also addressed, confirming that 1500 RPM equals 157 rad/s.
PREREQUISITESStudents studying physics, particularly those focusing on mechanics, engineers working with rotational systems, and anyone interested in understanding torque calculations in practical applications.
I get 6.67x10-2.CWatters said:Just for info I made it 6.45x10-2Nm