- #1

andorrak

- 30

- 0

## Homework Statement

A small sphere of radius r0 = 1.4 cm rolls without slipping on the track shown in the figure whose radius is R0 = 40.0 cm. The sphere starts rolling at a height R0 above the bottom of the track. Assume that it leaves the track after passing through an angle of 135° as shown.

Picture: http://imgur.com/7YLlJ

It asks for speed at the end of the ramp. and what is d.

## Homework Equations

I know all the basic equations. I am just confused how to get the height at the end of the ramp. ie. here's my equation.

E

_{0}=mgh or m(9.8)(.4)

E

_{1}=.5mv

^{2}+.5Iw

^{2}+mgh or

I replace "I" with the moment of inertia for a perfect sphere which is 2/5mr

^{2}

.5mv

^{2}+.5(2/5mr

^{2})v

^{2}+m(9.8)(h)

E

_{1}is the energy at the end of the ramp. But i cannot get h which is that height at the end of the ramp.

I figure the angle of that circle must be 45 degrees. So that arc length is .31m. Since the Radius is 40cm. Arc Length = angle times radius.

But i cannot get the height. If i get the height i can solve for the speed, then the get d.

Thanks ahead for any help.