Rotational Motion: The Relationship Between Linear and Angular Displacement

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In rotational motion, when a mass attached to a rope falls a distance x meters, the string must also move through x meters around the rim or disk. This relationship can be expressed mathematically as s = rθ, where s is the linear displacement, r is the radius, and θ is the angular displacement in radians. The discussion emphasizes that the linear distance fallen by the mass directly correlates to the angular distance traveled by the rim or disk. This connection highlights the conservation of distance in the system. Understanding this relationship is crucial for analyzing rotational dynamics effectively.
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Suppose a mass attached to a rope which winds around a rim or a disk. If the mass attached to the string falls x meters, should the string also move thorugh x meters around the rim or the disk which we can relate by s = r theta?
 
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Yes, it pretty much has to doesn't it? That "x" distance has to come from somewhere!
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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