Row reduction, Gaussian Elimination on augmented matrix

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SUMMARY

This discussion focuses on solving a matrix using Gaussian elimination, specifically addressing row reduction techniques on an augmented matrix. The participants emphasize the importance of performing operations row by row, utilizing row operations such as multiplication and subtraction to achieve the desired matrix form. Key steps include multiplying rows and substituting values to simplify the matrix, ultimately leading to a clearer representation of the equations involved. The conversation also highlights the necessity of demonstrating effort in problem-solving before seeking assistance.

PREREQUISITES
  • Understanding of Gaussian elimination techniques
  • Familiarity with augmented matrices
  • Knowledge of basic row operations (addition, subtraction, multiplication)
  • Ability to interpret linear equations from matrix form
NEXT STEPS
  • Practice Gaussian elimination on various augmented matrices
  • Learn about matrix row operations in detail
  • Explore online resources and YouTube tutorials on Gaussian elimination
  • Study the implications of row swapping in matrix equations
USEFUL FOR

Students studying linear algebra, educators teaching matrix operations, and anyone looking to improve their skills in solving systems of equations using Gaussian elimination.

Rafa3D
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Hi! Please, could you help me on how to solve the following matrix ?
I need to replace the value 3 on the third line by 0, the first column need to remain zero and 1 for the third column. I'm having a lot of difficulties with this. How would you proceed ?

1680987895171.png


Thank you for your time and help.
All best
 
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Usually you go row by row. Use the first row to knock out the first entry of the second row, then the first row to knock out the first entry of the third row, and then the second row to knock out the second entry of the third row. The first two parts are done for you in this matrix!
 
Office_Shredder said:
Usually you go row by row. Use the first row to knock out the first entry of the second row, then the first row to knock out the first entry of the third row, and then the second row to knock out the second entry of the third row. The first two parts are done for you in this matrix!
I m sorry, but I still don't understand :(
 
Why don't you start by listing out all the operations you can do.
 
Hi @Rafa3D. Welcome to PF.

The general rule here is that you have to show evidence of your own effort before we help. You will get guidance/steering/advice rather than answers. That being said…

Let’s use ‘R1’ as shorthand for 'row one' for example.

Q1. What would R2 be if you multiplied it by 3? Tell us what it would be.

Q2. Subtract your answer from R3 (four subtractions to do). You will get a new R3 but R1 and R2 haven’t changed. Tell us what the matrix is now.

If you answer Q1 and Q2 correctly, there’s one final step.

Note, there are many YouTube videos explaining this.
 
Steve4Physics said:
Hi @Rafa3D. Welcome to PF.

The general rule here is that you have to show evidence of your own effort before we help. You will get guidance/steering/advice rather than answers. That being said…

Let’s use ‘R1’ as shorthand for 'row one' for example.

Q1. What would R2 be if you multiplied it by 3? Tell us what it would be.

Q2. Subtract your answer from R3 (four subtractions to do). You will get a new R3 but R1 and R2 haven’t changed. Tell us what the matrix is now.

If you answer Q1 and Q2 correctly, there’s one final step.

Note, there are many YouTube videos explaining this.
Thank you. I think I got the idea :

1681049851166.png
 
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Rafa3D said:
Thank you. I think I got the idea :

View attachment 324667
Yes. You can skip some of the steps for brevity if you are comfortable with this. For example you don't really need to write
0*¼ 0*¼ 4*¼ | 8*¼
You could immediately write
0 0 1 | 2.

And you have labelled the rows of the final matrix as x, y and z on the left side. That's wrong here. Remember your final matrix represents these equations:
1.x + 1·y - 1·z = -2
0·x + 1·y - 1·z = -3
0·x + 0·y +1·z = 2

Also, you are allowed to swap rows, so it makes no sense to label a row as x or y or z.
 

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