Satellite synchronous to Venus' rotation

Click For Summary

Homework Help Overview

The discussion revolves around determining the altitude of a synchronous satellite orbiting Venus, which has a rotational period of 243 days. Participants explore the relationship between the satellite's orbit and Venus' rotation, focusing on concepts of centripetal acceleration and orbital mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the factors affecting satellite orbit duration, including centripetal acceleration and gravitational forces. There are attempts to relate the satellite's velocity to its orbital radius and period, with some questioning how to express these relationships mathematically.

Discussion Status

The discussion includes various attempts to derive equations for velocity and altitude, with some participants providing hints and guidance on the relationships between the variables involved. There is an ongoing exploration of the conditions necessary for synchronous orbit, but no consensus has been reached on the complete solution.

Contextual Notes

Participants note the importance of correctly interpreting the period of Venus and converting units appropriately. There is also mention of the need to clarify assumptions regarding the definitions of velocity and altitude in the context of synchronous orbits.

endeavor
Messages
174
Reaction score
0
Venus has a rotational period of 243 days. What would be the altitude of a syncom satellite for this planet?

I am pretty sure a syncom satellite is a satellite that orbits synchronously to the rotation of the planet.

I don't know how to solve this problem... help
 
Physics news on Phys.org
Think about what things affect how long it takes a satellite to go around in an orbit. And think about the basics of uniform central motion (something going in a circular path). What is the centripetal (sp?) acceleration that causes a mass to go around in a circle? How is that centripetal acceleration related to the speed of the mass? Now what is generating that force in the case of a satellite? What about Venus affects the centripetal acceleration of the satellite?
 
ac = v2/(RV + h)
but i don't know ac, v, or h...
v = squareroot of (G * MV / (RV + h))
but i still don't know v or h...

I found that the distance from venus to the sun is 108.2 * 10^9 m, so I figured that's 3.0 * 10^9 m/day. That means every day venus travels 3.0 * 10^9 m. Therefore the circumference of venus is 3.0 * 10^9 m? But that's not right...

I'm still not sure how I'm supposed to solve this...
 
endeavor said:
ac = v2/(RV + h)
but i don't know ac, v, or h...
v = squareroot of (G * MV / (RV + h))
but i still don't know v or h...

How might one express the velocity of the satellite in terms of the radius of the orbit and the period?

Hint: What is the shape of the orbit have to be for it to be synchronous? What does this say about how the satellite's speed changes throughout its orbit?
 
v = (2pi * r)/ T, where T is the period

I have
r = 6052000m + h, where h is the altitude
T=?
To find h, I would have to know v already...

The satellite has to orbit in a circle, and therefore it's speed doesn't change.
 
endeavor said:
T=?
You know T it is defined in your question...for the Earth T would be 24 hours so what is it for Venus? [Don't forget to change you units to seconds when doing the final calculation]
 
endeavor said:
The satellite has to orbit in a circle, and therefore it's speed doesn't change.

Good, and what is the other condition for it to be synchronous?
 
Okay, I finally got the right answer...
I thought 243 days meant that Venus has 243 days in its path around the sun.
Venus and the satellite have to have the same angular speed.
w=v2/(r + h)
I also have the equation for the speed of a satellite:
v2=square root of (GMV/(r + h))

Solving for the two unknowns, v2 and h, I get h = 1.53 * 10^9 m, which is the correct answer.

Thanks for all the great help! I really appreciate it!
 
Sorry, can you explain how you solved for v and then for h? I can see how it would be easy solving for the altitude once you know the v, but I don't know how to get to that.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
14
Views
2K
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K