What is the K.E. of the satellite?

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Homework Help Overview

The discussion revolves around calculating the kinetic energy (K.E.) of a satellite in a circular, sun-synchronous orbit at an altitude of 1300.0 km with a mass of 5,000.0 kg. The original poster expresses uncertainty about how to proceed from the kinetic energy formula they provided.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the forces acting on the satellite and its acceleration. There is a suggestion to consider the radius of the orbit and the implications of sun-synchronicity on the orbital period.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some guidance has been offered regarding the relationship between orbital characteristics and the calculations needed for kinetic energy, though there is no explicit consensus on the relevance of sun-synchronicity.

Contextual Notes

There is some confusion regarding the relevance of sun-synchronicity to the problem, with differing opinions on its importance in the context of calculating kinetic energy.

starchaser2020
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A satellite has been placed in a circular, sun-synchronous orbit at an altitude of 1300.0 km. The satellite has a mass of 5,000.0 kg. What is the K.E. of the satellite?

I know K=(1/2)mv^2 ... but I have no idea where to go from here. I Know I am over-thinking this. So any help would be greatly appreciated!
 
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What forces act on the satellite in that orbit? What is its acceleration?
(I don't think the sun-synchronicity needs to be taken into account.)
 
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Last edited:
PeroK said:
The sun synchronicity is telling you how long the satellite takes to orbit. You could actually work this out using the radius if you know enough about circular motion, as suggested by haruspex above.

But I suspect you won't know enough physics yet so you have been given the period of orbit.

How long does the sun take to "orbit" the earth?
Interesting... it's not a term I'd come across, so I looked it up before answering the post. My reading is that sun synchronicity is not directly related to orbital period. Indeed, I read that typical sun synchronous orbits are at around 500-600km and take under two hours. The term refers to the orbits being so arranged that the Earth's oblateness causes the orbit to precess one day per year, thereby always appearing the same from the sun's perspective. Hence it didn't seem relevant to me.
 
Yes, you're right. It's not about the period at all. Apologies.
 

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