Scalar triple product coplanarity

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SUMMARY

Vectors u, v, and w in R3 are coplanar if and only if the scalar triple product u · (v × w) equals zero. This condition indicates that vector u is orthogonal to the cross product of v and w, which implies that u lies in the same plane defined by v and w. The proof can be described geometrically by relating the scalar triple product to the volume of the parallelepiped formed by the vectors, which is zero when the vectors are coplanar.

PREREQUISITES
  • Understanding of vector operations, specifically dot product and cross product.
  • Familiarity with the concept of coplanarity in three-dimensional space.
  • Knowledge of geometric interpretations of vector products.
  • Basic principles of linear algebra and vector spaces.
NEXT STEPS
  • Study the geometric interpretation of the scalar triple product in R3.
  • Learn about the properties of vector orthogonality and coplanarity.
  • Explore the derivation and applications of the volume of a parallelepiped.
  • Investigate other vector identities and their implications in three-dimensional geometry.
USEFUL FOR

Students of linear algebra, geometry enthusiasts, and anyone studying vector calculus or physics related to three-dimensional space.

Neen87
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Homework Statement



Show that u, v, w lie in the same plane in R3 if and only if u · (v × w) = 0.


Homework Equations





The Attempt at a Solution



if u · (v × w) = 0, then u is orthogonal to vxw, and
vxw is orthogonal to v and w.

therefore, u must lie in the same plane determined by v and w (i.e. they are coplanar)


Is this correct? Also, how would i describe this proof mathematically?

Thanks!
 
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u · (v × w) = 0

use geometrical proof

translate the equation as volume of parallopiped
the volume is zero only when the height is zero
or all vectors lie in the same plane
 
Neen87 said:

Homework Statement



Show that u, v, w lie in the same plane in R3 if and only if u · (v × w) = 0.


Homework Equations





The Attempt at a Solution



if u · (v × w) = 0, then u is orthogonal to vxw, and
vxw is orthogonal to v and w.

therefore, u must lie in the same plane determined by v and w (i.e. they are coplanar)


Is this correct? Also, how would i describe this proof mathematically?

Thanks!
Yes, that's correct and, once you have stated exactly HOW you know that two vectors, perpendicular to the same non-zero vector, are co-planar, it IS "mathematical".

payumooli's suggestion is another way to do it but since you have already done it your own way, I suggest you stay with it.
 

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