Scattered State Solutions of a Repulsive Dirac Delta Potential

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The discussion centers on the relationship between the reflection and transmission coefficients of attractive and repulsive Dirac delta potentials. It confirms that the coefficients for the attractive Dirac delta potential -aδ(x) can be applied to the case of a repulsive delta potential as well. The reflection and transmission characteristics remain consistent across these scenarios. This equivalence highlights the underlying principles governing delta potentials in quantum mechanics. The analysis reinforces the validity of applying known solutions from one case to another.
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Homework Statement
For a repulsive Dirac delta potential V = a##\delta##(x), find the scattered state solutions.
Relevant Equations
##\beta## = ##\frac{4\pi^{2}m\alpha}{h^{2}k}##
##k^{2}## = ##\frac{8\pi^{2}mE}{h^2}##
I feel that this problem can be directly answered from the E>0 case of the attractive Dirac delta potential -a##\delta##(x), with the same reflection and transmission coefficients. Can someone confirm this hunch of mine?
 
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Yes, your hunch is correct. The attractive Dirac delta potential -a##\delta##(x) is a special case of the more general problem of an attractive delta potential V(x). The reflection and transmission coefficients for the attractive Dirac delta potential -a##\delta##(x) are the same as those for the more general case of an attractive delta potential V(x).
 
At first, I derived that: $$\nabla \frac 1{\mu}=-\frac 1{{\mu}^3}\left((1-\beta^2)+\frac{\dot{\vec\beta}\cdot\vec R}c\right)\vec R$$ (dot means differentiation with respect to ##t'##). I assume this result is true because it gives valid result for magnetic field. To find electric field one should also derive partial derivative of ##\vec A## with respect to ##t##. I've used chain rule, substituted ##\vec A## and used derivative of product formula. $$\frac {\partial \vec A}{\partial t}=\frac...