Schrodinger Equation for Potential Well

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SUMMARY

The discussion focuses on solving the time-independent Schrödinger equation (TISE) for a particle of mass m with total energy E < 0 confined in a potential well. The wavefunction given is Nx exp(-αx), and participants confirm that substituting this wavefunction into the TISE demonstrates it is indeed a solution for x > 0. The process involves calculating the second derivative of the wavefunction and rearranging to find the energy eigenvalue E, which is derived as a constant multiple of the wavefunction.

PREREQUISITES
  • Understanding of the time-independent Schrödinger equation (TISE)
  • Familiarity with wavefunctions and their properties
  • Knowledge of derivatives and their application in quantum mechanics
  • Concept of energy eigenvalues in quantum systems
NEXT STEPS
  • Study the derivation of energy eigenvalues in quantum mechanics
  • Learn about boundary conditions in quantum potential wells
  • Explore the implications of wavefunction normalization
  • Investigate the role of potential wells in quantum mechanics
USEFUL FOR

Students of quantum mechanics, physicists working with wavefunctions, and anyone studying the Schrödinger equation and its applications in potential wells.

freddy_12345
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Homework Statement


A particle of mass m and total energy E < 0 is confined to a potential given by:
1.jpg

where [tex]\alpha[/tex] is some positive constant.

Show that the wavefunction
3.jpg

is a solution of the time independent Schrödinger equation when x > 0. Find the associated energy Eigenvalue E.

Homework Equations


The TISE:
2.jpg

The Attempt at a Solution


The second part of the question is straightforward: you take the equation for [tex]\psi[/tex](x) and its second derivative and plug them into the TISE, cancel and rearrange for E. I got:
4.jpg

Which I'm over 50% sure is correct.

But for the first part, what does it mean to show that Nx exp (-[tex]\alpha[/tex]x) is a solution?
 
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freddy_12345 said:
The second part of the question is straightforward: you take the equation for [tex]\psi[/tex](x) and its second derivative and plug them into the TISE, cancel and rearrange for E. I got:
4.jpg

Which I'm over 50% sure is correct.

But for the first part, what does it mean to show that Nx exp (-[tex]\alpha[/tex]x) is a solution?

You've basically already done the first part. All you need to do is plug it into the left-hand side of the TISE, calculate the derivatives and show that for x>0, you get a constant times the wavefunction for all values of x>0. Doing so, proves that it is a solution to the TISE (If it weren't, then you would not end up with a constant multiple of the wavefunction when you calculate the LHS). The second part simply asks you for the value of that constant (E).
 

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