Schwarzschild metric as induced metric

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Discussion Overview

The discussion revolves around the embedding of the Schwarzschild metric within higher-dimensional spaces, specifically exploring whether pseudoremannian manifolds can be isometrically embedded in pseudoeuclidean spaces. The scope includes theoretical considerations of general relativity and mathematical implications of embedding theorems.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • Some participants reference Nash's theorem, questioning its applicability to pseudoremannian manifolds and the possibility of finding a submanifold in pseudoeuclidean space that induces the Schwarzschild metric.
  • One participant cites Chris Clarke's work, stating that every 4-dimensional spacetime can be isometrically embedded in a higher-dimensional flat space, with 90 dimensions being sufficient for all spacetimes.
  • Another participant claims that 6 dimensions are needed to embed a Schwarzschild solution, suggesting that all general relativity solutions can be locally embedded in 10 dimensions.
  • A follow-up question challenges the assertion about needing 6 dimensions for the Schwarzschild solution, asking for the basis of that claim.

Areas of Agreement / Disagreement

Participants express differing views on the dimensionality required for embedding the Schwarzschild solution, with some asserting 6 dimensions and others referencing the broader context of 90 dimensions for general spacetimes. The discussion remains unresolved regarding the exact dimensional requirements.

Contextual Notes

The discussion includes assumptions about the nature of embeddings and the specific characteristics of the Schwarzschild metric, which may not be fully articulated or agreed upon by all participants.

paweld
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According to Nash theorem http://en.wikipedia.org/wiki/Nash_embedding_theorem" every Riemannian manifold can be isometrically embedded
into some Euclidean space. I wonder if it's true also
in case of pseudoremanninan manifolds. In particular is it possible to find
a submanifold in pseudoeuclidean space that, the metric induced on it will be
Schwarzschild metric? How many dimensions we need?
 
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Chris Clarke* showed that every 4-dimensional spacetime can be embedded isometically in higher dimensional flat space, and that 90 dimensions suffices - 87 spacelike and 3 timelike. A particular spacetime may be embeddable in a flat space that has dimension less than 90, but 90 guarantees the result for all possible spacetimes.

* Clarke, C. J. S., "On the global isometric embedding of pseudo-Riemannian
manifolds," Proc. Roy. Soc. A314 (1970) 417-428
 
You need 6 dimensions to embed a Schwarzschild solution. I think that all GR solutions can be (locally) embedded in 10 dimensions.
 
Passionflower said:
You need 6 dimensions to embed a Schwarzschild solution.
How do you know it?
 

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