Scientific notebook/maple help

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The discussion focuses on solving the equation (x-13)²+(y-31)²+16=441 using Maple's solve + exact function. The equation can be transformed into (x-13)²+(y-31)²=425, representing a circle centered at (13,31) with a radius of 5√17. To obtain numerical values for x and y, users can parameterize the circle using x = 13 + 5√17 cos(θ) and y = 31 + 5√17 sin(θ), where θ ranges from 0 to 2π.

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Hi, I'm meant to use the scientific notebook to answer equations but I'm stuck on one of the equations. I want to solve for x and y in: (x-13)^2+(y-31)^2+16=441. I used the solve + exact function in Maple because I need to find two variables, but the x and y values in the answers were decimals. When I solve for the x, it comes up with a complicated solution in terms of y, and when I try to sub that back into the equation, it won't solve. How am I meant to get numerical values for x and y?
 
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ninadg2@yahoo said:
Hi, I'm meant to use the scientific notebook to answer equations but I'm stuck on one of the equations. I want to solve for x and y in: (x-13)^2+(y-31)^2+16=441. I used the solve + exact function in Maple because I need to find two variables, but the x and y values in the answers were decimals. When I solve for the x, it comes up with a complicated solution in terms of y, and when I try to sub that back into the equation, it won't solve. How am I meant to get numerical values for x and y?

U mean u want to get value x=? and y=?
But its not possible ... u realize that u can change to equation to (x-13)²+(y-31)²=425
and that equation is non other than circle with centre at (13,31) ...
U need to input x to get y value or vice versa ...
(x,y) = (√(425)cosθ+13,√(425)sinθ+31)

θ=tan⁻¹(((y-31)/(x-13)))
 
Last edited:
Adding to what Icystrike said, since your circle has radius 5*sqrt(17) you could parameterize it:

x = 13 + 5*sqrt(17) cos(θ)
y = 31 + 5*sqrt(17) sin(θ).

Then let θ range from 0 to 2pi using as small steps as you like to print out lots of (x,y) pairs.
 

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