Second derivative of e^x minus e^x

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SUMMARY

The discussion confirms that the function y(t) = e^t is indeed a solution to the differential equation y'' - y = 0. The derivatives of e^t are straightforward, with y' = e^t and y'' = e^t, leading to the conclusion that y'' - y equals zero. The simplicity of this relationship highlights the direct nature of exponential functions in solving such equations. The exchange emphasizes the value of collaboration in problem-solving.

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Homework Statement


Show that y(t) = e^t is a solution of y'' - y = 0,

Homework Equations


integral of e^x dx = e^x +c
derivative of e^x = e^x



The Attempt at a Solution


set m = d(e^t)/dt, which also = e^t then dm = e^t

then d(m)/dt = e^t if y(t) = e^t is a solution
integrate both sides m= e^t +c
substitute e^t = e^t + c which is true for C = 0
not sure if it is that simple
 
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It's even more simple than that. Put y=e^t. y'=e^t. y''=e^t. y''-y=e^t-e^t=0. You don't need to say much more than that.
 
Thanks Dick! sometimes it just helps to be able to ask someone else to look at it.
 

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