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Can someone please help me figure out how to calculate the second moment of area for a hollow isosceles triangle? Is there an equation available somewhere? Or can I simply subtract a smaller triangle from a larger one, using the equation I=bh

^{3}/36? (so I= b

_{1}h

_{1}

^{3}/36 -b

_{2}h

_{2}

^{3}/36)

Also, is there any way to account for the base wall being thicker than the sides?

Thank you!