Interpreting the Second Moment of Area and Euler's Formula Values

In summary, the higher the Second Moment Of Area value, the more resistant to buckling a column will be. Conversely, a lower Second Moment Of Area value means the column is less resistant to buckling. The critical buckling load can be calculated using Euler's formula, and in the case of a column with different values for Ix and Iy, it will buckle first in the direction with the lower Second Moment Of Area value.
  • #1
tomtomtom1
160
8
Hi all

I was hoping someone could remove some doubt in my mind with regards to interpreting the Second Moment Of Area and Eulers formula for buckling.

Am I correct in thinking that:-
- The higher the Second Moment Of Area Value the more resistant to bending.
- The lower the Second Moment Of Area Value the less resistant to bending.

Using Eulers formula for buckling I have calculated the critical load for a column in the X and Y axis, my values are:-

Ix = 25.39N
Iy = 634N

Am I correct in interpreting these results as the column will buck in the x-axis first because it will only take 25.39N of load before it buckles - is this correct?

I can do the math it is the concept I struggle with (doesn't help that I have a crap tutor).

thank you.
 
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  • #2
tomtomtom1 said:
Hi all

I was hoping someone could remove some doubt in my mind with regards to interpreting the Second Moment Of Area and Eulers formula for buckling.

Am I correct in thinking that:-
- The higher the Second Moment Of Area Value the more resistant to bending.
- The lower the Second Moment Of Area Value the less resistant to bending.
Buckling is a function of Young’s modulus, E, Boundary conditions , column length , and the Moment of inertia, I. For 2 columns of the same material and length and support conditions, the one with the smaller I will have a lower critical buckling load, as one might expect. Although a column bends when it buckles, I’d use the term “resistance to buckling “ rather than “resistance to bending “.Note that a perfectly straight ideal column with a compressive load applied axially will never buckle; there must be a slight initial deformation or eccentric load before it does. Also, if it is below a certain length, it will crush and fail before it ever buckles.
Using Eulers formula for buckling I have calculated the critical load for a column in the X and Y axis, my values are:-

Ix = 25.39N
Iy = 634N

Am I correct in interpreting these results as the column will buck in the x-axis first because it will only take 25.39N of load before it buckles - is this correct?
yes, correct, provided that the column is not restrained in that direction.
 

1. What is the second moment of area and how is it calculated?

The second moment of area, also known as the moment of inertia, is a measure of an object's resistance to bending. It is calculated by taking the integral of the cross-sectional area of an object multiplied by the square of its distance from the axis of rotation.

2. How is the second moment of area used in engineering and physics?

The second moment of area is used to determine the stiffness and strength of an object. It is commonly used in engineering and physics to analyze the behavior of beams, columns, and other structural elements under different loading conditions.

3. What is Euler's formula and what does it represent?

Euler's formula, also known as the buckling formula, is a mathematical equation used to determine the critical buckling load of a slender column. It represents the relationship between the applied load, the material properties of the column, and its length.

4. How are the second moment of area and Euler's formula related?

The second moment of area is a factor in Euler's formula, as it represents the moment of inertia of the cross-sectional area of the column. This value is used to calculate the critical buckling load and determine the stability of the column under compressive loads.

5. What are the limitations of using the second moment of area and Euler's formula?

The second moment of area and Euler's formula assume certain idealized conditions, such as a perfectly straight and homogeneous column. In reality, these conditions may not be met, leading to potential inaccuracies in the calculations. Additionally, these calculations do not take into account other factors such as material imperfections or external forces, so they should be used with caution and in conjunction with other engineering principles.

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