Second order linear differential operator

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SUMMARY

The discussion focuses on the properties of second order linear differential operators, specifically the operator L acting on a function f defined over an interval J. It establishes that if y can be expressed as the sum of a function u (where Lu = 0) and another function v (where Lv = f), then Ly = f holds true. Conversely, if Ly = f, it can be shown that y can be decomposed into u and v, confirming the linearity of the operator L.

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  • Understanding of second order linear differential operators
  • Knowledge of linearity in mathematical operators
  • Familiarity with function decomposition in differential equations
  • Basic concepts of vector spaces and zero vectors
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  • Explore the method of undetermined coefficients for solving differential equations
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Ready2GoXtr
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Homework Statement


Suppose that L is a second order linear differential operator over the interval J, that f is a function defined on J, and that the function v has the property that

Lv = f on J

(a) Show that if y = u + v and that Lu = 0 on J, then Ly = f on J
(b) Show that if Ly = f on J, then y = u + v for some u such that Lu = 0 on J

Homework Equations


None that apply

The Attempt at a Solution


Well unfortunately this one I was unable to attempt because i am not even sure what it is asking, this professor I have tends to deviate from the book.
 
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Ready2GoXtr said:

Homework Statement


Suppose that L is a second order linear differential operator over the interval J, that f is a function defined on J, and that the function v has the property that

Lv = f on J

(a) Show that if y = u + v and that Lu = 0 on J, then Ly = f on J
(b) Show that if Ly = f on J, then y = u + v for some u such that Lu = 0 on J

Homework Equations


None that apply

The Attempt at a Solution


Well unfortunately this one I was unable to attempt because i am not even sure what it is asking, this professor I have tends to deviate from the book.

(a) If L is linear, then L(u+v)=Lu+Lv. So if we have Lu=0, then

Ly=L(u+v)=Lu+Lv=0+Lv=Lv=f.

(b) Since L is linear, then there is a zero vector u with Lu=0 and 0+y=y. Choose u=0 and v=y. Then u+v=0+y=y.
 
Thanks man I would never figure that out!
 

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