Second order nonlinear differential equation

Click For Summary
SUMMARY

The discussion focuses on the analytical solution of the second-order nonlinear differential equation y''(x) = A - B [exp(y(x)/C) - 1], where A, B, and C are constants. The equation can be simplified to a form involving z = y/C, leading to z'' = A" - B'e^z, with A" and B' defined as A'/C and B/C, respectively. The transformation allows for the use of numerical integration techniques, as the final form indicates that an analytical solution is not feasible.

PREREQUISITES
  • Understanding of second-order nonlinear differential equations
  • Familiarity with exponential functions and their properties
  • Knowledge of numerical integration techniques
  • Basic concepts of variable substitution in differential equations
NEXT STEPS
  • Research numerical integration methods such as Runge-Kutta or Euler's method
  • Explore the use of software tools like MATLAB or Python's SciPy for solving differential equations
  • Study the implications of variable substitution in differential equations
  • Learn about stability analysis in nonlinear differential equations
USEFUL FOR

Mathematicians, physicists, and engineers involved in solving complex differential equations, particularly those interested in numerical methods and nonlinear dynamics.

equation M
Messages
6
Reaction score
0
Is it possible to solve the following differential equation analytically?

y''(x) = A - B [exp(y(x)/C) - 1]

where A, B and C are constants.


Thank you...
 
Physics news on Phys.org
that can be simplified to
y'= A- Be^{y/C}- B= (A- B)- Be^{y/C}= A'- Be^{y/C}
with A- B= A'
and if you let z= y/C, y= Cz, so y''= Cz'' and the equation becomes
Cz''= A'- Be^z or z''= A"- B'e^z
with A"= A'/C and B'= B/C.

Since the independent variable, x, does not appear in that, let u= z' so that z''= u'= (du/dz)(dz/dx)= u(du/dz) and the equation becomes
u(du/dz)= A"- B'e^z so udu= (A"- B'e^z)dz and, integrating,
(1/2)u^2= A"z- B'e^z+ C

So u= dz/dt= sqrt(2(A"z- B'e^z+ C))

dt= dz/sqrt(2(A"z- B'e^z+ C))

That looks like it cannot be integrated analytically but at least it is set up for a direct numerical integration.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K