1. The problem statement, all variables and given/known data Find the general solution of the following diff. eqn. y''(t) + 4y'(t) + 4y(t) = t^(-2)*e^(-2t) where t>0 2. Relevant equations General soln - Φgeneral(t) + Φparticular(t) Wronskian - Φ1(t)Φ22'(t) - Φ2(t)Φ1'(t) 3. The attempt at a solution I'm solving by variation of parameters. First solving for the general solution, y'' + 4y' + 4y = 0 r2 + 4r + 4 which factors into (r+2)(r+2), so r = -2, -2. So the gen solution is y = c11e^(-2t) + c2e^(-2t) Now solving for the particular solution. Φ1 and Φ2= e^(-2t) The Wronskian here ends up being 2e^(-4t) - 2e^(-4t) which equals zero. What went wrong here? I know the Wronskian cannot equal zero here. This is where I am stuck.