Self induction in a straight wire

[jpo]

Direct current I in a straight wire is decreasing with time. Let's assume dI/dt is large. Will such change produce self-induced current in the direction of I?


If Lenz's law is an equivalent of Newton's 3rd law, how come changes in straight wire meet no resistance?

 

[jpo]

It seems to me that the system has to react against the change. Is this true?

 

[ctech4285]

i think that is where inductivity comes from or the resistance of change of current. and you need a large field to push the current throw the wire.

 

[jpo]

My question is will there be such inductance. I mean, there is no loop and no flux through it

 

[ctech4285]

yes. you don't need a loop. a strait wire will do the trick.

 

[thehacker3]

any change in current through any object, whether it be a coil or a straight wire, will produce a magnetic field (inductance). The relationship of inductance to the change in current is calculated by lenz's law

 

[jpo]

Current decreases with time. Self induction has to presumably supply extra Amps to resist the change. Where will the energy com from to do all this?

 

[mrspeedybob]

Current decreases with time. Self induction has to presumably supply extra Amps to resist the change. Where will the energy com from to do all this?

The magnetic field stores energy. This energy was put there as the current ramped up.

 

[jpo]

mrspeedybob,
this seems very reasonable, thank you!