How Does Coil Configuration Affect Solenoid Inductance?

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SUMMARY

The discussion centers on the calculation of self-inductance for two solenoids made from copper wire, where the first solenoid has 3n turns and a radius of r, while the second has n turns and a radius of 3r. The formula for self-inductance, L = μN²A/l, is applied incorrectly, leading to a 1:1 ratio. The correct ratio of self-inductance is established as 3:1, based on the assumption that both coils are made from wire of the same length and have the same number of turns per unit length, resulting in different solenoid lengths.

PREREQUISITES
  • Understanding of solenoid inductance and the formula L = μN²A/l
  • Basic knowledge of coil geometry and dimensions
  • Familiarity with the concept of turns per unit length in solenoids
  • Knowledge of magnetic permeability (μ) and its role in inductance
NEXT STEPS
  • Study the derivation of the self-inductance formula for solenoids
  • Explore the effects of coil geometry on inductance in different configurations
  • Learn about the practical applications of solenoid inductance in electrical circuits
  • Investigate the impact of wire material and dimensions on inductance
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Electrical engineers, physics students, and anyone involved in designing or analyzing inductive components in circuits will benefit from this discussion.

Rayanna
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Two coils are made of copper wires of same length .In the first coil number of turns is 3n and radius is r . In the second coil number of turns is n and radius is 3r the ratio of self inductances of the coil is:

I know that self inductance of a solenoid is μN2A/l ;
where A = area of cross section of frame of solenoid ;so by puting values I get 1:1 which is incorrect ? Please explain me where I am wrong as the correct answer is 3:1.
 
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Rayanna said:
Two coils are made of copper wires of same length .In the first coil number of turns is 3n and radius is r . In the second coil number of turns is n and radius is 3r the ratio of self inductances of the coil is:

I know that self inductance of a solenoid is μN2A/l ;
where A = area of cross section of frame of solenoid ;so by puting values I get 1:1 which is incorrect ? Please explain me where I am wrong.

It's a sort of trick question. Hint: what is "length" in this context?
 
PeroK said:
It's a sort of trick question. Hint: what is "length" in thi
PeroK said:
It's a sort of trick question. Hint: what is "length" in this context?
I am not sure but may be copper wires are of same length.
But then I can't find the length of solenoid
 

##l## is the length of the solenoid. Is that the same in both cases? The total length of the wire is the same.

Also, what is ##N##? Is that the same in both cases?
 
PeroK said:
##l## is the length of the solenoid. Is that the same in both cases? The total length of the wire is the same.

Also, what is ##N##? Is that the same in both cases?
I am also not sure that length of solenoid is same, as it is not cleary stated in question that whether copper wires used to make coil are of same length or coils are of same length but N in first case is 3n and in second case is n.
 
Rayanna said:
I am also not sure that length of solenoid is same, as it is not cleary stated in question that whether copper wires used to make coil are of same length or coils are of same length but N in first case is 3n and in second case is n.

You are told that the wire is the same length in both cases, and I think you are supposed to assume that the wire is coiled with the same number of coils per unit length in both cases. This would give you:

##r_1 = r, \ N_1 = 3n, \ l_1 = l##

##r_2 = 3r, \ N_2 = n, \ l_2 = l/3##

The solenoid must be shorter in th second case, where the length is each coil is longer.
 
PeroK said:
You are told that the wire is the same length in both cases, and I think you are supposed to assume that the wire is coiled with the same number of coils per unit length in both cases. This would give you:

##r_1 = r, \ N_1 = 3n, \ l_1 = l##

##r_2 = 3r, \ N_2 = n, \ l_2 = l/3##

The solenoid must be shorter in th second case, where the length is each coil is longer.
Thanks for the solution.
But still I did not understand the point that why we should assume that number of turns per united length is same?
 
Rayanna said:
Thanks for the solution.
But still I did not understand the point that why we should assume that number of turns per united length is same?

If you make the solenoid the same length in both cases, then your 1-1 ratio is correct. It might seem quite natural to do this in order to comapre the inductance in the two cases.

But, another natural approach is to coil the wire equally in both cases (probably tightly). This leads to different lengths of solenoid in the two cases.

On reflection, I would say the second assumption is better, because you can definitely do that. In the first case, you may have to stretch the wire and the loops are less and less like circles if the radius is large.

A diagram might help.
 
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PeroK said:
If you make the solenoid the same length in both cases, then your 1-1 ratio is correct. It might seem quite natural to do this in order to comapre the inductance in the two cases.

But, another natural approach is to coil the wire equally in both cases (probably tightly). This leads to different lengths of solenoid in the two cases.

On reflection, I would say the second assumption is better, because you can definitely do that. In the first case, you may have to stretch the wire and the loops are less and less like circles if the radius is large.

A diagram might help.
Thank you.

I get it so we have to assume both copper wires are of same length and we have coiled them in such manner that there number of turns per unit length are same.
 

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