Semiconductors, minimum conductivity

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SUMMARY

The minimum conductivity of a semiconductor is achieved when the carrier concentration in the conduction band, n0, equals ni√(μh/μe). The equation for minimum conductivity is derived from the relationship σ = e(n0μe + ni²/n0 μh). For silicon, intrinsic conductivity can be calculated using the intrinsic carrier concentration and mobility values, with assumptions regarding temperature and material properties. The discussion emphasizes the importance of differentiating the conductivity equation with respect to n0 to find the minimum value.

PREREQUISITES
  • Understanding of semiconductor physics, specifically carrier concentrations
  • Familiarity with the equations of conductivity in semiconductors
  • Knowledge of electron and hole mobility (μe and μh)
  • Basic calculus for differentiation and optimization
NEXT STEPS
  • Learn about the derivation of the intrinsic carrier concentration (ni) in semiconductors
  • Study the impact of temperature on semiconductor conductivity, specifically σ(T)
  • Explore the relationship between mobility and temperature, particularly the model µ=µoT^-0.6
  • Investigate the effects of doping on semiconductor properties and conductivity
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Students studying semiconductor physics, electrical engineers, and researchers focusing on material properties and conductivity optimization in semiconductors.

leonmate
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Homework Statement



Show that the minimum conductivity of a semiconductor occurs when n0 = ni√(μhe)

Derive an equation for the minimum conductivity

Calculate the (i) minimum and (ii) intrinsic conductivity for silicon. State the assumptions you make and the origin of any material properties used

Homework Equations


Some equations I've dug out of my notes that look revelant:

conductivity, σ = enμe + epμh = σe + σh
Number of electrons in conduction band: n0 = niexp(Ei - Ef / kT)

The Attempt at a Solution



I'm a little stuck on where to start with this one,
I know that ni is the intrinsic carrier concentration, n0 is the carrier concentration in the conduction band.

μh and μe are hole and electron mobility. This is the constant of proportionality between the drift velocity and the electric field. So the some of the electrons drift into the conduction band

Seems obvious that conductivity is at a minimum when there is as few electrons as possible in the conduction band, so I guess I need to do something with that. But I really need a hint or two here as I'm struggling to solve this problem. It's due tomorrow! >_<

Cheers
 
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Do you remember that in a semiconductor n*p = ni2?
 
yeah, i have that eq written down, trying to work out where to go from that...
 
So write n = n0 and p = ni2 / n0, then write σ in terms of n0 (eliminating n and p), then find the value of n0 that minimizes σ.
 
σ = e(n0μe + ni2/n0 μh)

I'm not really sure what to do with this, also where did n = n0 come from?
 
Ah, brainwave...

phyzguy said:
So write n = n0 and p = ni2 / n0, then write σ in terms of n0 (eliminating n and p), then find the value of n0 that minimizes σ.

σ = e(n0μe + ni2/n0 μh)

Then differentiate wrt n and set equal to zero to find the minimum. Rearrange and got it!
 
Great!
 
a. Calculate conductivity σ as function of temperature σ(T) for following semiconductors:Eg=0.4 eV, Nd=1e15 cm-3; Ec-Ed=0.02, Nc=Nv=1e19;
Use temperature from 80K to 500K, step 1K. For mobility, use µ=µoT-0.6 with µo=20,000.

can anybody help me out with this question.
 

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