Sequences and series help / recurrence relation

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SUMMARY

The discussion centers on solving a recurrence relation defined as U_{k+2} = U_{k+1} - pU_{k}, with initial conditions U_{1} = 2 and U_{2} = 4. The expressions derived for U_{3} and U_{4} are U_{3} = 4 - 2p and U_{4} = 4 - 6p, respectively. Given that U_{4} is twice U_{3}, the equation 4 - 6p = 2(4 - 2p) can be solved to find the value of p. The solution yields p = -2.

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Homework Statement



A sequence of terms [tex]U_{k}[/tex] is defined by [tex]K \geq[/tex] by the recurrence relation [tex]U_{k+2} = U_{k+1} - pU_{k}[/tex] where P is a constant Given that [tex]U_{1} =2[/tex] and [tex]U_{2} = 4[/tex]

a) find an expression in terms of p for [tex]U_{3}[/tex]

b) hence find an expression in terms of p for [tex]U_{4}[/tex]

given also that [tex]U_{4}[/tex] is twice the value of [tex]U_{3}[/tex]
c) find the value of p

The Attempt at a Solution



for question a i just subsititue k=1 and i get [tex]U_{3} = 4 - 2p[/tex] and for B i substituted k=2 and the expression i got is [tex]U_{4} = 4-6p[/tex]

what i am really stuck on is how to work out the value of 'p' ?

can anyone please show me ?

thanks!
 
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tweety1234 said:

Homework Statement



A sequence of terms [tex]U_{k}[/tex] is defined by [tex]K \geq[/tex] by the recurrence relation [tex]U_{k+2} = U_{k+1} - pU_{k}[/tex] where P is a constant Given that [tex]U_{1} =2[/tex] and [tex]U_{2} = 4[/tex]

a) find an expression in terms of p for [tex]U_{3}[/tex]

b) hence find an expression in terms of p for [tex]U_{4}[/tex]

given also that [tex]U_{4}[/tex] is twice the value of [tex]U_{3}[/tex]
c) find the value of p

The Attempt at a Solution



for question a i just subsititue k=1 and i get [tex]U_{3} = 4 - 2p[/tex] and for B i substituted k=2 and the expression i got is [tex]U_{4} = 4-6p[/tex]

what i am really stuck on is how to work out the value of 'p' ?

can anyone please show me ?

thanks!
Excellent! You have done exactly what you should have done. Now use that last condition, U4 is twice the value of U3 or U4= 3U3 with the U3 and U4 you have and solve for p.
 

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