Sequences: Monotones, Supermum, Infimum, Min & Max, and Convergence Explained

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SUMMARY

The discussion focuses on analyzing a sequence defined by the terms a1=1, a2=1/4, a3=1/27, a4=1/256, and a5=1/3125. The sequence is confirmed to be decreasing, as demonstrated by the inequality a(n+1) ≤ an. The user seeks clarification on defining supremum, infimum, minimum, and maximum, as well as proving the convergence of the sequence. The correct form of the sequence is identified as (1/n)^3, necessitating adjustments in the limit calculations for convergence analysis.

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Homework Statement



For the sequence (see picture), explore its monotones, define supermum and infimum, minimum and maximum, and find if the sequence is convergent. If the sequence is convergent, find form where on the terms of this sequence differ from the limit for less than ε = 0.01.

The Attempt at a Solution



a1= 1
a2= 1/4
a3= 1/9
a4= 1/16
a5= 1/25

Concussion: the sequence is decreasing.

Prove:
a(n+1) ≤ an
(1/n+1)^n ≤ (1/n)^n
(1/n+1)^n – (1/n)^n ≤ 0

Since (1/n+1)^n will always be smaller than (1/n)^n, I concluded that the left side will always be smaller than 0. I think this is the prove that the sequence is decreasing.

Now, I stuck. How do you know if the the sequence is monotonic, how can I define supermum and infimum, min and max? And how can I prove if it is convergent or not?
 

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From the terms you give, your sequence appears to be (1/n)2, not (1/n)n. The argument you gave in your limit has to be adjusted for this.
 
Ooops, my bad. It was a typo. It should be like this:

a1= 1
a2= 1/4
a3= 1/27
a4= 1/256
a5= 1/3125
 

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