Sequences & Series: Limit to Determine Convergence/Divergence

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SUMMARY

The discussion centers on determining the convergence or divergence of sequences, specifically using the example of the sequence defined by f(n) = 3^n/n^3. It is established that if the limit of a sequence approaches infinity, as in this case, the sequence diverges. The theorem referenced confirms that a sequence that does not converge to zero cannot have a convergent series. Therefore, since the limit is not a finite number, the sequence diverges to infinity.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with sequences and series in mathematical analysis
  • Knowledge of convergence and divergence theorems
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the formal definitions of convergence and divergence of sequences
  • Learn about theorems related to sequences and series, such as the Divergence Test
  • Explore examples of convergent sequences and their limits
  • Investigate the relationship between sequences and their corresponding series
USEFUL FOR

Students of mathematics, educators teaching calculus, and anyone interested in understanding the behavior of sequences and series in mathematical analysis.

arctic_girl4
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How do you know if a sequence converges or diverges based on taking the limit?

here's an example
f:= 3^n/n^3;

if i take the limit the sequence goes to infinity.

does it diverge because the limit is not zero or can the limit be something other than zero and it still converge?
 
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You are talking about a sequences and not series? You titled this "sequences and series". There is a theorem that says that if a sequence does not converge to 0, then the series (infinite sum) of those numbers cannot converge but certainly if a sequence converges to any number then it converges!

However in this case the sequence "goes to" infinity, as you say, and infinity is not a number. The sequence diverges. Many textbooks would say this sequence "diverges to infinity".
 

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