- #1
JasonJo
- 429
- 2
I need help proving that if (xn) is a convergent series, then (xn)^2 is a convergent series.
also is (n^3)*(xn) is convergent, then (xn) is convergent. i reasoned that if (n^3)*(xn) is convergent, we know that (n^3)*(xn) > (xn) > 0, therefore by comparison test, (xn) is convergent.
determine whether or not the function exists and if it doesn't explain why:
lim x--> 0 (x^2/(|x|))
i can't put it in formal terms why this limit does not exist (we did not go over continiuty yet)
show that the function
f(x) = { x if x is rational, 0 if x is irrational
has a limit at p=0 and does not have a limit at any other point.
can't quite establish that the limit exists and how do i prove that no other points have limits?
also is (n^3)*(xn) is convergent, then (xn) is convergent. i reasoned that if (n^3)*(xn) is convergent, we know that (n^3)*(xn) > (xn) > 0, therefore by comparison test, (xn) is convergent.
determine whether or not the function exists and if it doesn't explain why:
lim x--> 0 (x^2/(|x|))
i can't put it in formal terms why this limit does not exist (we did not go over continiuty yet)
show that the function
f(x) = { x if x is rational, 0 if x is irrational
has a limit at p=0 and does not have a limit at any other point.
can't quite establish that the limit exists and how do i prove that no other points have limits?