Series Convergence: \sum_{n=2}^{\infty}\frac{1+n+n^2}{\sqrt{1+n^2+n^6}}

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The series \(\sum_{n=2}^{\infty} a_n\) where \(a_n = \frac{1+n+n^2}{\sqrt{1+n^2+n^6}}\) diverges. The initial assumption that \(a_n > \frac{1}{n}\) for several values of \(n\) is insufficient for proving divergence. Instead, by dividing the terms by \(n^2\) and analyzing the limit as \(n\) approaches infinity, it is established that the series diverges without needing to prove the inequality for all \(n\).

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Determine whether the series [tex]\sum_{n=2}^{\infty}a_n[/tex] converges absolutely,converges conditionally or diverges.If

[tex]a_n=\frac{1+n+n^2}{\sqrt{1+n^2+n^6}}[/tex]


For several n I get [tex]a_n>\frac{1}{n}[/tex] so I decided that this series is divergent.Right?
 
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That would do it. But did you prove that inequality? Just looking at 'several n' basically means you are guessing.
 
In fact the result can be much weaker, we don't need to prove the inequality for all n, or even that a_n is more than 1/n, just equal. Divide the terms through by n^2 and see what the n-th term as n --> infinity is.
 

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