MHB Series Question Concering Convergence/Divergence

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Determine whether the sequence converges or diverges.

$$a_n = \frac{(-1)^{n + 1} n}{n + \sqrt{n}}$$

Ok, so if I'm understanding this correctly, I need to just ignore the sign and think of this particular problem as leading coefficient over leading coefficient to get $$\frac{n}{n} = 1$$?

Also, then wouldn't that mean that $$\lim a_n$$ as $${n\to\infty} = 1$$ ?

So since a limit exists wouldn't it converge to 1? What is the logic that is insinuating that this is divergent? I am not seeing it. Maybe I'm looking at this incorrectly?
 
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The sequence ends up oscillating between 1 and -1. So, it diverges.
 
shamieh said:
Determine whether the sequence converges or diverges.
The title thread says "Series", but the question says, "sequence". Which is it? Or did you mean, "Serious question"? :)

shamieh said:
$$a_n = \frac{(-1)^{n + 1} n}{n + \sqrt{n}}$$

Ok, so if I'm understanding this correctly, I need to just ignore the sign and think of this particular problem as leading coefficient over leading coefficient to get $$\frac{n}{n} = 1$$?
You could do this.

shamieh said:
Also, then wouldn't that mean that $$\lim a_n$$ as $${n\to\infty} = 1$$ ?
Here you can't ignore the sign.

shamieh said:
So since a limit exists wouldn't it converge to 1?
What do you mean by "it": $a_n$ or $\sum_{k=1}^n a_k$?
 
Sequence, not Series. Typo.

So in any case where something is oscillating back and forth would $$a_n$$ as $$n$$ approaches $$\infty$$ always be divergent or no?
 
shamieh said:
Sequence, not Series. Typo.

So in any case where something is oscillating back and forth would $$a_n$$ as $$n$$ approaches $$\infty$$ always be divergent or no?

If a series is oscillating between two (or more) values, it can't converge to one value. So, it is divergent.
 
Exactly the question I was asking, awesome, thanks.
 

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