Series RLC - calculate V w/ different ƒ

[dwn]

Homework Statement

Series RLC - Band Pass Filter[/B]
R = 2700Ω
V_i = 5 Vpp
C = 10 nF
L = 33 mH
I need to find the voltage across the resistor for different frequencies.

Homework Equations

w = 2pi*ƒ
V = R*V_i / (jwL + 1/jwC+R)

The Attempt at a Solution

This is from a lab experiment. How can I use the source voltage, R and ƒ_r to find the voltage across R at different frequencies.

-----update -----
sorry about that. new values added above.

 

[gneill]

Homework Statement

Series RLC - Band Pass Filter[/B]
R = 2700Ω
V_i = 5 Vpp
I need to find the voltage across the resistor for different frequencies.

Homework Equations

w = 2pi*ƒ
V = R*V_i / (jwL + 1/jwC+R)

The Attempt at a Solution

This is from a lab experiment. How can I use the source voltage, R and ƒ_r to find the voltage across R at different frequencies.

You haven't given all the information required: What are the values of L and C?

 

[gneill]

Your relevant equations are indeed relevant. You've correctly written a voltage divider equation which will give you the voltage across the resistor for values of Vi and f. Of the the result will be a complex value. You might try reducing it to magnitude and angle (polar) form. In the lab, what device (test equipment) was used to read the output voltage?

 

[dwn]

We used an oscilloscope to read the measured values, now I have to calculate the data with the given data for comparison. Then find the percentage error.

 

[gneill]

We used an oscilloscope to read the measured values, now I have to calculate the data with the given data for comparison. Then find the percentage error.

Okay. So you'll have recorded values for the waveform peaks, thus the voltage magnitudes, for various frequencies. You can use your voltage divider equation to calculate the voltage and determine the theoretical magnitude values. Again, you might want to reduce the formula to a magnitude version.