Convergence or Divergence of Series with Square Roots

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Homework Help Overview

The discussion revolves around determining the convergence or divergence of the series \(\sum (\sqrt{k} - \sqrt{k - 1})^k\). The subject area includes series convergence tests and properties of square roots.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the expression \(\sqrt{k} - \sqrt{k - 1}\) and its simplification. There are attempts to apply the root test and comparisons to known divergent series. Questions arise about the relevance of certain limits and tests being used.

Discussion Status

The discussion is ongoing, with participants providing insights and guidance on the application of convergence tests. Some participants express confusion regarding the tests being applied and the implications of their findings.

Contextual Notes

There is a mention of confusion regarding the notation and terminology, specifically the introduction of \(\mu\) without prior context. Participants are encouraged to maintain a broader perspective on the problem rather than getting lost in details.

zeion
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Homework Statement



Determine whether the series converges or diverges.

\sum (\sqrt {k} - \sqrt {k - 1})^k


Homework Equations





The Attempt at a Solution



(a_k)^\frac{1}{k} = \sqrt{k} - \sqrt{k - 1}

What do I do here..?

= \frac{1}{\sqrt{k} + \sqrt{k-1}} \to 0 ?
 
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I would start with this:
\sqrt{k} - \sqrt{k - 1} = \frac{(\sqrt{k} - \sqrt{k - 1})(\sqrt{k} + \sqrt{k - 1})}{\sqrt{k} + \sqrt{k - 1}}
 
So that is
<br /> \sqrt{k} - \sqrt{k - 1} = \frac{(\sqrt{k} - \sqrt{k - 1})(\sqrt{k} + \sqrt{k - 1})}{\sqrt{k} + \sqrt{k - 1}}<br /> = \frac {\sqrt{k}^2 - \sqrt{k-1}^2}{\sqrt{k} + \sqrt{k - 1}} = \frac{1}{\sqrt{k} + \sqrt{k-1}}
 
Then

\frac{1}{\sqrt{k} + \sqrt{k-1}} &lt; \frac{1}{\sqrt{k}} = ( \frac{1}{k})^{\frac{1}{2}? then converges?
 
You are apparently confusing yourself. You started with the root test, not the comparison test.

BTW, the series whose general term is 1/sqrt(k) diverges, but that's not relevant to what you're doing.
 
Ok so I go here \frac{1}{\sqrt{k} + \sqrt{k-1}} and then I'm kinda stuck
 
Take the limit as k --> infinity. What do you get? Why is this limit important to you? What did you start out doing in your first post?
 
I get 0? So the ratio is < 1 so its converges?
 
The limit is < 1. Try not to confuse yourself into think you are working with the ratio test - here it's the root test, so the fact that you are finding the limit of a fraction is not relevant.
 
  • #10
Ok so since a_k &lt; \mu^k and \mu^k converges a_kconverges
 
  • #11
I don't know -- what's \mu? That's the first time it has appeared in this thread.

zeion, you need to step back and take a bigger-picture view of what you're doing. You seem to be getting lost in minute details, and losing track of the purpose of the details.

Maybe it will help you grasp the overall strategy by answering these questions.
  1. What test are you using?
  2. When you use this test, what result indicates that the series you're testing converges?
    What result indicates that the series diverges?
  3. What result did you get?
  4. What can you conclude about the series you are testing?
 

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