Set builder notation question.

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SUMMARY

The discussion centers on the interpretation of the set S = {n ∈ Z | n = (-1)^k, for some integer k}. Participants clarify that S represents all integers since k can be any integer, leading to n being either positive or negative integers, including zero. The confusion arises from the notation and the role of k, with emphasis on the correct interpretation that every integer can be expressed as n = (-1)^k for some integer k. Thus, the conclusion is that S encompasses all integers.

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Jim01
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Homework Statement



Use the set-roster notation to indicate the elements in each of the following sets.


Homework Equations



S = {nZ |n(-1)k, for some integer k}


The Attempt at a Solution



Here is how I read this:

"S is the set of all n’s that are a member of the integers, such that n=(-1)k for some integer k."

I am confused about how to go about indicating the elements in this set. Specifically, how does k fit into the picture? If k can be any integer, then would n not also be any integer? Changing k would change n wouldn't it? If this is true then wouldn't the elements be all integers?
 
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Jim01 said:

Homework Statement



Use the set-roster notation to indicate the elements in each of the following sets.


Homework Equations



S = {nZ |n(-1)k, for some integer k}
From what you have below, this description should say n = (-1)k. IOW, you have omitted the equal sign.
Jim01 said:

The Attempt at a Solution



Here is how I read this:

"S is the set of all n’s that are a member of the integers, such that n=(-1)k for some integer k."

I am confused about how to go about indicating the elements in this set. Specifically, how does k fit into the picture? If k can be any integer, then would n not also be any integer? Changing k would change n wouldn't it? If this is true then wouldn't the elements be all integers?
If I understand what you have described, S is the set of all integers. If k is an integer, then -k is in S. Here k can be negative or positive (or zero). No matter which integer you take for k, such as 3, -5, or 0, -k (equallying, respectively, -3, -(-5) = 5, or 0) is still an integer.
 

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