Set Notation Question: Converting to Set Builder Notation | Homework Help

Click For Summary
The discussion revolves around converting a specific set into set builder notation. Two valid expressions were provided: { x = 1/2^n : n ∈ ℤ } and { x = 2^n : n ∈ ℤ }. Both answers are considered correct since they represent the same set, as one can be derived from the other through the relationship between positive and negative exponents. It is noted that neither expression is preferred over the other in a testing context. Ultimately, both notations accurately describe the same mathematical concept.
Rijad Hadzic
Messages
321
Reaction score
20

Homework Statement


So I have the set

{...(1/8),(1/4),(1/2),(1),(2),(4),(8)...}

I am suppose to put it in set builder notation..

Homework Equations

The Attempt at a Solution


my answer was {x = {\frac {1}{2^n} : n \in ℤ }}

but my books was

{x = {{2^n} : n \in ℤ }}

I understand both answers to be true. But would my answer be valid say, on a test or something. Is one of these preferred over the other?
 
Physics news on Phys.org
Rijad Hadzic said:

Homework Statement


So I have the set

{...(1/8),(1/4),(1/2),(1),(2),(4),(8)...}

I am suppose to put it in set builder notation..

Homework Equations

The Attempt at a Solution


my answer was {x = {\frac {1}{2^n} : n \in ℤ }}

but my books was

{x = {{2^n} : n \in ℤ }}

I understand both answers to be true. But would my answer be valid say, on a test or something. Is one of these preferred over the other?
In any but a brain-dead computerized quiz, both should be recognized as correct. IMO, neither one would be preferred over the other.
 
Mark44 said:
In any but a brain-dead computerized quiz, both should be recognized as correct. IMO, neither one would be preferred over the other.

Okay thank you. I just wanted to make sure..
 
Rijad Hadzic said:
Okay thank you. I just wanted to make sure..

The reason they are equivalent is that
$$ 2^{-n} = \frac{1}{2^n}, \: \text{and} \; 2^n = \frac{1}{2^{-n}}, $$
so that when ##n## runs through all positive and negative integers, for every ##n \in \mathbb{Z}## value of ##2^n## is matched exactly by ##1/2^m##, where ##m \in \mathbb{Z}##.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K