Set Theory: Is {a} a Subset of {S}?

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SUMMARY

The discussion centers on the relationship between sets in set theory, specifically whether the set {a} is a subset of another set S. The participant proposes S = {{a}, b}, asserting that {a} belongs to S but is not a subset. The correct interpretation is clarified: for {a} to be a subset of S, 'a' must be an element of S, not wrapped in additional brackets. The distinction between elements and subsets is emphasized, with examples provided to illustrate the concept.

PREREQUISITES
  • Understanding of basic set theory concepts
  • Familiarity with the definitions of subsets and elements
  • Knowledge of notation used in set theory
  • Ability to differentiate between single elements and sets containing elements
NEXT STEPS
  • Study the definitions of subsets and proper subsets in set theory
  • Learn about power sets and their significance in set theory
  • Explore examples of set operations, including union and intersection
  • Investigate the implications of set membership and element relationships
USEFUL FOR

Students studying set theory, educators teaching mathematical concepts, and anyone seeking to clarify the distinctions between sets and their elements.

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Homework Statement


I am not sure if set theory is precalc or not but here is my question.

Find a pair set such that {a} belongs to the set and {a} is not a subset of S.


The Attempt at a Solution


So I thought that a set like this would work S = {{a}, b} because {a} belongs to the set, but in order for {a} to be a subset it has to be wrapped in more brackets so {{a}} is a subset. Am I right? If not what did I state that was wrong?
 
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The example you have chosen is alright ,but the reasoning doesn't looks okay .For {a} to be a subset , 'a' should be an element of the set ,not {{a}} .For example for the set {a,b} , the subsets can be {a,b},{a},{b},ø . For set {{a},b} , the subsets can be {{a},b} , {{a}} ,{b} , ø .
 
Yea I realized my explanation was wrong but ny reasoning was the same as yours
 

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