Fermat1
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Am I right in thinking that if we have 3 sets A,B,C, then with A intersect B represented as AB, we have:
A(B\C)=(AB)\C=B(A\C)?
A(B\C)=(AB)\C=B(A\C)?
The discussion confirms that for three sets A, B, and C, the expression A(B\C) equals (AB)\C, which is equivalent to B(A\C). This conclusion is derived from the definition of set difference and the properties of set intersection. All three sets can be represented as A ∩ B ∩ ¬C, where ¬C denotes the complement of set C. The participants agree on the validity of these set operations.
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