Sets: A,B,C - Intersection & Difference

Click For Summary
SUMMARY

The discussion confirms that for three sets A, B, and C, the expression A(B\C) equals (AB)\C, which is equivalent to B(A\C). This conclusion is derived from the definition of set difference and the properties of set intersection. All three sets can be represented as A ∩ B ∩ ¬C, where ¬C denotes the complement of set C. The participants agree on the validity of these set operations.

PREREQUISITES
  • Understanding of set theory concepts, including intersection and set difference.
  • Familiarity with set notation and symbols, such as ∩ and ¬.
  • Knowledge of basic mathematical logic and proofs.
  • Ability to manipulate and interpret set expressions.
NEXT STEPS
  • Study the properties of set operations in detail, focusing on intersection and union.
  • Learn about Venn diagrams to visualize set relationships.
  • Explore advanced topics in set theory, such as cardinality and power sets.
  • Investigate applications of set theory in computer science, particularly in database management.
USEFUL FOR

Mathematicians, computer scientists, students studying discrete mathematics, and anyone interested in the fundamentals of set theory and its applications.

Fermat1
Messages
180
Reaction score
0
Am I right in thinking that if we have 3 sets A,B,C, then with A intersect B represented as AB, we have:

A(B\C)=(AB)\C=B(A\C)?
 
Physics news on Phys.org
Yes. This follows from the definition of set minus.
 
All three sets equal $A\cap B\cap\bar{C}$ where $\bar{C}$ is the complement of $C$.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 30 ·
2
Replies
30
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
7K