- #1

jonthebaptist

- 17

- 0

[itex]\frac{\partial T}{\partial t}=A\nabla^{2}T+BQ[/itex]

My PDE text gives Q as power delivered per unit volume. So substituting in the electrical power delivered divided by the differential volume element, I get

[itex]\frac{\partial T}{\partial t}=A\nabla^{2}T+B\frac{I^{2}\rho}{dx^{2}dz^{2}}[/itex]

What I did makes sense to me physically, but I am not sure if it makes sense mathematically as a PDE with a term having differential elements instead of derivatives.