What is the solution to the heat equation with a constant added?

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SUMMARY

The solution to the heat equation with a constant added, represented as $$\frac{\partial^2 u(x,t)}{\partial x^2} = k^2 \frac{\partial u(x,t)}{\partial t} + 2$$, can be approached by using the method of separation of variables. To solve this modified partial differential equation (PDE), one can decompose the solution into two parts: $$u = U + V$$, where $$V$$ satisfies the equation $$\frac{d^2V}{dx^2} = 2$$ under the same boundary conditions as $$u$$. This approach allows for the determination of the function $$U$$, which is essential for finding the complete solution.

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morenopo2012
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I have seen how to solve the heat equation:

$$ \frac{ \partial^2 u(x,t) }{\partial x^2} = k^2 \frac{ \partial u(x,t) }{\partial t} $$

With boundary conditions.

I use separation variables to find the result, but i don't know how to solve the equation plus a constant:

$$ \frac{ \partial^2 u(x,t) }{\partial x^2} = k^2 \frac{ \partial u(x,t) }{\partial t} + 2 $$How can i solve the second PDE?
 
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morenopo2012 said:
I have seen how to solve the heat equation:

$$ \frac{ \partial^2 u(x,t) }{\partial x^2} = k^2 \frac{ \partial u(x,t) }{\partial t} $$

With boundary conditions.

I use separation variables to find the result, but i don't know how to solve the equation plus a constant:

$$ \frac{ \partial^2 u(x,t) }{\partial x^2} = k^2 \frac{ \partial u(x,t) }{\partial t} + 2 $$How can i solve the second PDE?
Write $$u=U+V$$ where V satisfies the equation:
$$\frac{d^2V}{dx^2}=2$$
subject to the boundary conditions on u. See what that gives you for U.
 

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