A cubical block of ice of mass m and edge L is placed in
a large tray of mass M. If the ice melts, how far does the
center of mass of the system "ice plus tray" come down ?
The Attempt at a Solution
What I thought was that if no net force is acting on the system then position of center of mass should not change. But the answer in my text is mL/2(m+M). Can somebody explain me why is there a shift in center of mass.
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