Short Exact Sequence: Explaining C = B/A

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In the discussion about the short exact sequence 0-->A-->B-->C-->0, it is clarified that the mapping from A to B is injective, meaning it embeds A into B, while the mapping from B to C is surjective. The relationship C = B/A arises from the natural mapping of B to the quotient B/A, which represents the elements of B that are not in the image of A. This understanding is reinforced by the properties of exact sequences in algebraic topology and homological algebra. The participants engage in explaining these concepts, leading to a clearer comprehension of the sequence's implications. Overall, the discussion enhances the understanding of the fundamental properties of exact sequences in mathematics.
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http://en.wikipedia.org/wiki/Exact_sequence
Let's look at the following short exact sequence:
0-->A-->B-->C-->0.

Since the sequence is exact, the mapping from A-->B will be invective and the mapping B-->C will be subjective. The wikipedia article says that we can think of the mapping A-->B as a mapping that embeds A into B. It also says that we can think of the mapping from B-->C as the natural mapping of B-->B/A, and that B/A = C.Can anyone explain why this is? Why must C = B/A?
EDIT: I understand now, thanks anyone PF
:P
 
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