Short Grade 12 Gravitational Problem

Click For Summary
SUMMARY

The discussion centers on calculating the orbital period of Planet X, which has half the mass and triple the radius compared to Planet V, known to have a year lasting 360 days. The derived formula for the orbital period is T = sqrt(4π²r³/GM), where the variables represent gravitational constant (G), mass (M), and radius (r). By substituting the values for Planet V and Planet X into the formula, the final calculation yields the orbital period for Planet X as TX = sqrt((2)(3)³(360)²). This method effectively demonstrates the relationship between mass, radius, and orbital period.

PREREQUISITES
  • Understanding of gravitational physics, specifically Kepler's laws of planetary motion.
  • Familiarity with the formula T = 2πr/v and its derivation.
  • Knowledge of gravitational constant (G) and its significance in orbital mechanics.
  • Ability to manipulate algebraic equations and perform substitutions in formulas.
NEXT STEPS
  • Study Kepler's Third Law of Planetary Motion for further insights into orbital periods.
  • Learn about gravitational forces and their impact on planetary motion.
  • Explore the implications of mass and radius on orbital dynamics using simulation tools.
  • Investigate the effects of varying mass and radius on the stability of orbits in different celestial systems.
USEFUL FOR

Students studying physics, particularly those focusing on celestial mechanics, astrophysics enthusiasts, and educators teaching gravitational concepts in high school curricula.

TheSerpent
Messages
12
Reaction score
0
The Question
The Planet V has a year lasting 360 days. In the same star system is the Planet X. The Planet X has half the mass and triple the radius. A planet X year would be approximately _____ days
The attempt at a solution

Givens:
Tv= 360days
Tx= ?
mv = mv
mx = 1/2mv
rv = rv
rx = 3rvI derived a formula that incorporates time.
From which v = sqrt ( GM/r )
since T = 2pir / v

sub v into that formula and you get:

T = sqrt (4 pi^2 r^ 3 / GM )

with that I had two sets of values, Vulcan and X:
I plugged them into the formula and arranged for a common values such as Mv.
Then I subbed Mv from one formula into another.

This is what results:

8pi^23rv^3 / GTx^2 = 4pi^2rv^3/ GTv^2

through cancellations I ended up getting:

Tx = sqrt ( (2)(3)^3(360)^2 )
which was that amount of days.

Not sure if this method would be the correct way to go with this question or not.
 
Physics news on Phys.org
TheSerpent said:
The Question
The Planet V has a year lasting 360 days. In the same star system is the Planet X. The Planet X has half the mass and triple the radius. A planet X year would be approximately _____ days

The attempt at a solution

Givens:
TV= 360days
TX= ?
mV = mV
mX = 1/2mV
rV = rV
rX = 3rV

I derived a formula that incorporates time.
From which v = sqrt ( GM/r )
since T = 2(pi)r / v

sub v into that formula and you get:

T = sqrt (4 pi2 r3 / GM )

with that I had two sets of values, Vulcan and X:
I plugged them into the formula and arranged for a common values such as MV.
Then I subbed MV from one formula into another.

This is what results:

8pi23rv3 / GTx2 = 4pi2rv3/ GTv2

through cancellations I ended up getting:

TX = sqrt ( (2)(3)3(360)2 )
which was that amount of days.

Not sure if this method would be the correct way to go with this question or not.
Do you mean that the radius of the orbit of planet X is triple that of planet V ?

Does the mass of the planet matter? Is the M in the equation, v = sqrt ( GM/r ), the mass of the planet, or the mass of some other object?

Use the subscript, X2, & superscript, X2, buttons above the "Go Advanced" message box.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 23 ·
Replies
23
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K